概要: ck筫b_ChT?Sb楋y a箯?/p>hT?箯?times;4 C=4ab楋y=箯?times;箯?nbsp; S=a×a0ck筫SOV:SO飝 a:駂?/p>h坆楋y=駂?times;駂?times;6 Sh?a×a×6SO飝=駂?times;駂?times;駂?nbsp; V=a×a×a0暪eb_ChT?Sb楋y a箯?/p>hT?(?絒)×2 C=2(a+b)b楋y=?times;絒 S=ab暪eSOV:SO飝 s:b楋y a:?b: 絒 h:貧(1)h坆楋y(?times;絒+?times;貧+絒×貧)×2S=2(ab+ah+bh)(2)SO飝=?times;絒×貧 V=abhN覊b_sb楋y a昢 h貧b楋y=昢×貧÷2 s
\GSRpef[Y`ND崣e郠UOlQ_,标签:小考数学,http://www.laixuea.comck筫b_
ChT?Sb楋y a箯?/p>
hT?箯?times;4 C=4a
b楋y=箯?times;箯?nbsp; S=a×a0
ck筫SO
V:SO飝 a:駂?/p>
h坆楋y=駂?times;駂?times;6 Sh?a×a×6
SO飝=駂?times;駂?times;駂?nbsp; V=a×a×a0
暪eb_
ChT?Sb楋y a箯?/p>
hT?(?絒)×2 C=2(a+b)
b楋y=?times;絒 S=ab
暪eSO
V:SO飝 s:b楋y a:?b: 絒 h:貧
(1)h坆楋y(?times;絒+?times;貧+絒×貧)×2
S=2(ab+ah+bh)
(2)SO飝=?times;絒×貧 V=abh
N覊b_
sb楋y a昢 h貧
b楋y=昢×貧÷2 s=ah÷2
N覊b_貧=b楋y ×2÷昢
N覊b_昢=b楋y ×2÷貧
s^L堐V箯b_
sb楋y a昢 h貧
b楋y=昢×貧 s=ah
痟b_
sb楋y a N昢 bN昢 h貧
b楋y=( N昢+N昢)×貧÷2 s=(a+b)× h÷2
Wb_
Sb楋y ChT?∏ d=魐刜 r=JS刜
魐刜=JS刜×2 d=2r JS刜=魐刜÷2 r= d÷2
W剉hT?WhT噑×魐刜=WhT噑×JS刜×2 c=πd =2πr
W剉b楋y=WhT噑×JS刜×JS刜 =πr0
W駁SO
v:SO飝 h:貧 s;昢b楋y r:昢b桱S刜 c:昢b梙T?/p>
(1) W駁剉b楋y=昢b?W剉hT?times;貧 S=ch
(2)h坆楋y=b楋y+昢b楋y×2
(3)SO飝=昢b楋y×貧 V=Sh
(4)SO飝b楋y÷2×JS刜0
W%昐O
v:SO飝 h:貧 s;昢b楋y r:昢b桱S刜
SO飝=昢b楋y×貧÷3